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23 August, 11:44

21.7 mL of gas at 98.8 kPa is allowed to expand at constant

temperature into a 52.7 mL container. What is the new

pressure of the gas?

kPa.

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Answers (1)
  1. 23 August, 12:13
    0
    Answer: 40.68 kPa

    Explanation:

    Given that,

    Original volume of gas V1 = 21.7 mL

    Original pressure of gas P1 = 98.8 kPa

    New volume of gas V2 = 52.7 mL

    New pressure of gas P2 = ?

    Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

    P1V1 = P2V2

    98.8 kPa x 21.7 mL = P2 x 52.7L

    2143.96 kPa L = 52.7 L x P2

    P2 = 2143.96 kPa L / 52.7 L

    P2 = 40.68 kPa

    Thus, the new pressure of the gas is 40.68 kPa.
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