How many grams of AgNO3 are needed to prepare a 0.25 m solution in 500 grams of water?

Question 2 options:

125 g

0.125g

21.25 g

170g

Volume = V = 250ml = 0.25 L

M = 0.135M

Molar mass of AgNO3 = 108+14+3*16 = 170

M = mole/V

mole = 0.135*0.25 = 0.03375 mole

mole = mass/molar mass

mass = 0.03375 * 170 = 5.7375 gr