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23 October, 17:22

How many grams of AgNO3 are needed to prepare a 0.25 m solution in 500 grams of water?

Question 2 options:

125 g

0.125g

21.25 g

170g

+2
Answers (1)
  1. 23 October, 17:51
    0
    Volume = V = 250ml = 0.25 L

    M = 0.135M

    Molar mass of AgNO3 = 108+14+3*16 = 170

    M = mole/V

    mole = 0.135*0.25 = 0.03375 mole

    mole = mass/molar mass

    mass = 0.03375 * 170 = 5.7375 gr
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