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10 July, 06:23

The rate constant for this first‑order reaction is

0.200

s

-

1

at

400



C.

A



products

How long, in seconds, would it take for the concentration of

A

to decrease from

0.950

M

to

0.300

M?

t

=

s

+4
Answers (1)
  1. 10 July, 06:51
    0
    t = 5.7634 s

    Explanation:

    A → Pdts - rA = K (CA) ∧α = - δCA/δt

    ∴ T = 400°C

    ∴ α = 1 ... first-order

    ∴ CAo = 0.950 M

    ∴ CA = 0.300 M

    ⇒ t = ?

    ⇒ - δCA/δt = K*CA

    ⇒ - ∫δCA/CA = K*∫δt

    ⇒ Ln (CAo/CA) = K*t

    ⇒ t = Ln (CAo/CA) / K

    ⇒ t = (Ln (0.950/0.300)) / (0.200 s-1)

    ⇒ t = 1.1527 / 0.200 s-1

    ⇒ t = 5.7634 s
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