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7 October, 13:46

How many moles of nh3 can be produced from 13.5 mol of h2 and excess n2?

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  1. 7 October, 13:57
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    Standard equation: N2 (g) + 3H2 (g) = = >2NH3 (g), so through stoichiometry, (13.5 mol H2) (2 mol NH3/3 mol H2), yielding 9 moles of NH3
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