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28 January, 22:56

How many kJ are required to completely vaporize a 25.0 gram sample of water at 100°C?

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  1. 28 January, 23:19
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    You have to use the latent heat of vaporization of the water.

    The latent heat of vaporization of water at 100 °C is approximately 2.26 kJ / g (search this number in some tables; you will find similar numbers aroung 2.23 and 2.26 kJ/g).

    Now mutiply 25.0 g * 2.26 kJ / g and you will get 56.5 kJ

    The answer is approximately 56.5 kJ.
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