Adding helium to a balloon increased its volume from 358.5 ml to 2.262 l. if the final number of moles of helium in the balloon is 14.6 mol, what was the initial number of moles of helium in the balloon? assume the balloon contained only helium initially.

Question

Sydney Grant

Chemistry

12 August, 11:58

Adding helium to a balloon increased its volume from 358.5 ml to 2.262 l. if the final number of moles of helium in the balloon is 14.6 mol, what was the initial number of moles of helium in the balloon? assume the balloon contained only helium initially.

+2

Answers (2)

Know the Answer?

Whitney Franco · Answer 1

0.08 mol

Explanation:

Easy clap too lazy to add an explanation but at least I'm not wrong.

Danica Blankenship · Answer 2

Answer : 2.31 moles of Helium was initially present in the balloon.

Explanation : Calculating the initial number of moles of helium in the balloon we need to use this method,

final moles present - 14.6 mol

Volume increased from 358.5 mL ( = 0.3585 L) to 2.26 L

(14.6 mol) x (0.3585 L / 2.26 L) = 14.6 moles X 0.158 L = 2.31 moles / L

Hence, the initial moles was 2.31 moles/L in the helium balloon.