The Concentration of C6H12O6 May be represented as?

A 12 oz Coca Cola contains 39g of sugar or C6H12O6.

To calculate for the molarity of sugar in the soda, convert 39 grams of sugar to moles sugar:

39g / 180.16 g/mol = 0.216 mol sugar

then, convert 12 oz to L:

12oz / (1oz/0.02957L) = 0.35484 L

therefore the concentration of sugar in the soda is:

M = mol sugar / L sol'n

= 0.216 mol sugar / 0.35484 L

= 0.609 M

therefore the concentration of sugar in the soda is:

M = mol sugar / L sol'n

= 0.216 mol sugar / 0.35484 L

= 0.609 M