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13 July, 00:45

The analysis of an organic compound showed that it contained 0.630 mol of C, 0.0300 mol of H, 0.420 mol of O, and 0.210 mol of N. How many nitrogen atoms are there in the empirical formula for this compound?

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  1. 13 July, 01:03
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    The empirical formula is C21HO14N7

    Explanation:

    Step 1: Data given

    Number of moles of C = 0.630 moles

    Number of moles H = 0.0300 moles

    Number of moles O = 0.420 moles

    Number of moles N = 0.210 moles

    Step 2: Calculate the mol ratio

    We divide by the smallest amount of moles

    C: 0.630 moles / 0.0300 moles = 21

    H: 0.0300 moles / 0.0300 moles = 1

    O: 0.420 moles / 0.0300 moles = 14

    N: 0.210 moles / 0.0300 moles = 7

    The empirical formula is C21HO14N7
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