Given that the molar mass of NaCl is 58.44 g/mol, Solve for the molarity of a solution that contains 87.75 g of NaCl in 500 mL of solution.

A.) 0.333 M

B.) 0.751 M

C.) 1.50 M

D.) 3.00 M

Question

Jaylin Bowers

Chemistry

21 January, 15:43

Given that the molar mass of NaCl is 58.44 g/mol, Solve for the molarity of a solution that contains 87.75 g of NaCl in 500 mL of solution.

A.) 0.333 M

B.) 0.751 M

C.) 1.50 M

D.) 3.00 M

+1

Answers (1)

Know the Answer?

Pamela Sweeney · Answer 1

Most of the information's required for solving this question is already given. Let us now focus on the problem in hand.

Grams/Molar Mass = Moles

Molarity = Moles/Liters

The above formulas are important for solving this problem.

Number of moles of Nacl = 87.75/58.44

= 1.50

Molarity = Number of moles of solute (here NaCl) / Volume of solution in Liters

Then

Volume of solution in Liters = Number of moles of solute (here NaCl) / Molarity

Volume of solution in Liters = 500/1500

= 0.333 M

The correct option among all the options that are given in the question is the first option or option "A".

Given that the molar mass of NaCl is 58.44 g/mol, Solve for the molarity of a solution that contains 87.75 g of NaCl in 500 mL of solution.A.) 0.333 MB.) 0.751 MC.) 1.50 MD.) 3.00 M

Given that the molar mass of NaCl is 58.44 g/mol, Solve for the molarity of a solution that contains 87.75 g of NaCl in 500 mL of solution.

A.) 0.333 M

B.) 0.751 M

C.) 1.50 M

D.) 3.00 M