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9 June, 08:50

A 4.000 g sample of iron was heated from 0.0°C to 21.0°C. If it has a specific heat of 0.440 kJ/kg °C, how many kilojoules of heat does it absorb?

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  1. 9 June, 08:57
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    M = 4 g = 4/1000 kg = 0.004 kg, θ₂ = 21.0°C, θ₁ = 0°C, c = 0.44kJ/kg°C,

    Q = mc (θ₂ - θ₁)

    Q = 0.004*0.440 * (21 - 0)

    Q = 0.03696 kJ

    0.03696 kJ of heat is absorbed.
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