A man heats a balloon in the oven. If the balloon initially has a volume of 2.0 L and a temperature of 293K, what will the final temperature of the balloon be after he heats it and has a final volume of 10.0L?

The correct answer is 1465K

Explanation:

The formula to be used here is that of Charles' law.

Charles' law states that the volume of an ideal gas is directly proportional to its absolute temperature (in kelvin), provided that pressure remains constant. From the law above we can deduce the formula below

V₁/T₁ = V₂/T₂

where V₁ is the initial volume (2.0 L)

T₁ is the initial temperature (293K)

V₂ is the final temperature (10.0L)

T₂ is the final temperature (unknown)

From the formula, it can be deduced that

T₂ = (T₁ * V₂) : V₁

T₂ = (293 * 10) : 2

T₂ = 1465K

The final temperature of the balloon after heating will be 1465K