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4 May, 18:35

How many moles of potassium would you need to prepare 1200 grams of 5.0% potassium sulfate (m/m) solution

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  1. 4 May, 18:43
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    The moles of potassium that you would need to prepare 1200 g of 5% potassium sulfate solution is 1.538 moles

    calculation

    calculate the mass potassium using the below formula

    %M/M = mass of the solute (potassium) / mass of the solvent (potassium sulfate solution)

    let the mass of potassium be represented by Y

    then convert % into fraction = 5/100

    5/100 = Y/1200

    cross multiplication

    100y = 6000

    divide both side by 100

    Y = 60 g

    moles of potassium = mass/molar mass

    = 60/39=1.538
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