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22 April, 07:29

Kw at certain temperature? at a certain temperature, the ph of a neutral solution is 7.53. what is the value of kw at that temperature?

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  1. 22 April, 07:56
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    Remember that pH = - log[H⁺]

    So [H⁺] = 10^ (-pH)

    also recall that Kw for water would be:

    Kw = [H⁺][OH⁻]

    Remember that in water, the concentration of hydronium ions, or H⁺, will equal the concentration of hydroxide ions. That is [H⁺] = [OH⁻].

    [OH⁻] = [H⁺] = 10^ (-7.53) = 2.95*10^-8

    (The rules for significant digits is when you take 10 to the power of something with x significant decimal places, then the result will have x significant digits. But for now keep some extra digits so we won't have rounding errors.)

    Kw = (2.95*10^-8) * (2.95*10^-8) = 8.70*10^-16 = 8.7*10^-16

    The Kw is 8.7*10^-16.
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