22 August, 18:34
What is the atomic weight of an element if 4 grams of it contains 2.98 x 10^22 atoms?
22 August, 18:44
N=amount in moles
N=amount in numbers=2.98x10^22
L=Avagadro's constant=mole-1 (6.022x10^23)
m = mass in grams
M=molar mass in g/mol
=0.0495 mol ≈0.05 mol
The element is Br
22 August, 20:25
M = 4 g; N = 2.98 * 10^22
Avogadro constant: L = 6.022 * 10^23
Number of moles:
n = 2.98 * 10^22 : 6.022 * 10^23 = 0.298 * 10^23 : 6.022 * 10^23 =
= 0.0495 moles
M = m/n = 4 g / 0.0495 = 80.8 ≈ 80
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