Calculate the amount of energy released when 2,064 g of water are cooled from 92 ˚C to 45˚C. The specific heat of water is 4.184.

Answer: Q = - 405,881 J or - 405.88 kJ

Explanation: To find the amount of heat released we will use the formula of heat which is Q = mc∆T.

Q = 2,064 g (4.184 J/g°C) (45°C - 92°C)

= 2,064 g (4.184 J/g°C) (-47°C)

= - 405,881 J

Or we can convert this into kJ which is equal to - 405.88 kJ.