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8 May, 11:53

The molar heat of vaporization of water is 40.7 kJ mol. How much heat must be absorbed to convert 50.0 grams of liquid water at 100oC to steam at 100oC?

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  1. 8 May, 11:56
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    Molar mass of water 18g/mol

    Number of mols = 50.0g/18g/mol = 2.78 mol

    Heat absorbed = 40.7 kj/mol * 2.78 mol = 113.1 kj.
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