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30 April, 10:52

How many grams of ko2 are needed to form 6.5 g of o2?

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  1. 30 April, 11:01
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    Decomposition of a potassium superoxide happens according to the scheme:

    4KO₂ (s) + 2H₂O (l) → 4KOH (aq) + 3O₂ (g)

    m (K₂O) = 4M (K₂O) m (O₂) / {3M (O₂) }

    m (K₂O) = 4*71.1*6.5/{3*32.0}≈19.3 g
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