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29 August, 09:09

Consider the chemical equation.

2NBr3 + 3NaOH - - > N2 + 3NaBr + 3HOBr

If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?

N2

NBr3

NaOH

HOBr

+1
Answers (1)
  1. 29 August, 09:23
    0
    NBr₃ : NaOH = 2 : 3

    40 : 48 = 2 : 2.4

    40 : 48 = 2.5 : 3

    NBr₃ is the excess reactant
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