In an experiment, 26.5 g of metal was heated to 98.0°c and then quickly transferred to 150.0 g of water in a calorimeter. the initial temperature of the water was 20.0°c, and the final temperature after the addition of the metal was 32.5°c. assume the calorimeter behaves ideally and does not absorb or release heat.

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Chemistry

2 May, 12:44

In an experiment, 26.5 g of metal was heated to 98.0°c and then quickly transferred to 150.0 g of water in a calorimeter. the initial temperature of the water was 20.0°c, and the final temperature after the addition of the metal was 32.5°c. assume the calorimeter behaves ideally and does not absorb or release heat.

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Hubbard · Answer 1

This is a common laboratory experiment called calorimetry which determines the specific heat capacity of the sample metal.

By the Conservation of Energy,

Energy of Metal = Energy of Water

mCmetalΔT = mCwaterΔT, wherein Cwater = 4.187 J/g·°C

(26.5 g) (Cmetal) (98 - 32.5°C) = (150 g) (4.187 J/g·°C) (32.5 - 20°C)

Solving for Cmetal,

Cmetal = 4.523 J/g·°C