How many mL of a 2.50 M NaOH solution are required to make a 525 mL of a 0.150 M NaOH solution?

V₁ = 31.5 mL

Explanation:

Given dа ta:

Initial molarity = 2.50 M

Initial volume required = ?

Final molarity = 0.150 M

Final volume = 525 mL

Solution:

Formula:

M₁V₁ = M₂V₂

M₁ = Initial molarity

V₁ = Initial volume

M₂ = Final molarity

V₂ = Final volume

Now we will put the values in formula.

2.50 M * V₁ = 0.150 M * 525 mL

V₁ = 0.150 M * 525 mL / 2.50 M

V₁ = 78.75 M. mL / 2.50 M

V₁ = 31.5 mL