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30 September, 15:15

if 1200 j of heat were absorbed by a 25 g block of iron, by how much would the temperature of the iron increase?

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  1. 30 September, 15:34
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    m = mass of the block of iron = 25 g

    Q = heat absorbed by the block of iron = 1200 J

    ΔT = increase in the temperature of iron due to heat absorbed = ?

    c = specific heat of block of iron = 0.450 J / (g C)

    Heat absorbed by the block of iron is given as

    Q = m c ΔT

    inserting the values in the above formula

    1200 = 25 (0.450) ΔT

    1200 = (11.25) ΔT

    ΔT = 1200/11.25

    ΔT = 106.67 C
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