How can 100ml of sodium hydroxide solution with a ph of 13.00 be converted to a sodium hydroxide solution with a ph of 12.00?

Question

Justice

Chemistry

27 August, 18:27

How can 100ml of sodium hydroxide solution with a ph of 13.00 be converted to a sodium hydroxide solution with a ph of 12.00?

+4

Answers (1)

Know the Answer?

Jaylin Parsons · Answer 1

Chemical reaction: NaOH (aq) → Na⁺ (aq) + OH⁻ (aq).

V₁ (NaOH) = 100 mL : 1000 mL/L = 0.1 L.

pOH = - log[OH⁻].

pH + pOH = 14.

pOH₁ = 14 - 13 = 1.

pOH₂ = 14 - 12 = 2.

[OH⁻]₁ = 10∧ (-pOH₁) = 10⁻¹ M = 0.1 M.

[OH⁻]₂ = 10 (-pOH₂) = 10⁻² M = 0.01 M.

[OH⁻]₁ · V₁ (NaOH) = [OH⁻]₂ · V₂ (NaOH).

0.1 M · 0.1 L = 0.01 M · V₂ (NaOH).

V₂ (NaOH) = 1 L, we can add 900 mL of water to convert solution of sodium hydroxide from pH=12 to pH=13, or we can add some strong acid.