If you obtained 2.50 moles of CuSO4 from the reaction of CuO and H2SO4, but the theoretical yield was 3.19 moles, what was the percent yield?

78.4%

Explanation:

Just as context, write the chemical equation and the mole ratios

1) Balanced chemical equation:

CuO (s) + H₂SO₄ (aq) → CuSO₄ (aq) + H₂O (l)

2) Therotetical (stoichiometric) mole ratios:

1 mol CuO : 1 mol H₂SO₄ : 1 mol CuSO₄ : 1 mol H₂O

You can calculate the percent yield from the amount of CuSO₄ obtained and the theoretical yield

3) Percent yield

Definition:

Percent yield = (actual yield / theoretical yield) * 100

Theoretical yiedl (given) : 3.19 moles CuSO₄

Actual yield (given) : 2.50 moles CuSO₄

Calcualtion:

Substitute the values in the formula:

Percent yield = (2.50 moles CuSO₄ / 3.19 moles CuSO₄) * 100 = 78.4%