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21 June, 14:04

If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of gas

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  1. 21 June, 14:21
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    The answer to your question is V2 = 29.6 l

    Explanation:

    Data

    Pressure 1 = P1 = 12 atm

    Volume 1 = V1 = 23 l

    Temperature 1 = T1 = 200 °K

    Pressure 2 = 14 atm

    Volume 2 = V2 = =

    Temperature 2 = T2 = 300°K

    Process

    1. - To solve this problem use the Combine gas law.

    P1V1/T1 = P2V2/T2

    -Solve for V2

    V2 = P1V1T2 / T1P2

    2. - Substitution

    V2 = (12) (23) (300) / (200) (14)

    3. - Simplification

    V2 = 82800 / 2800

    4. - Result

    V2 = 29.6 l
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