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15 June, 10:51

Question 1

Acetone (CH3) 2CO is a volatile Liquid that can be readily converted to vapour.

Calculate the density of acetone vapour at 100,000 Pa and 398 K in kg/m3. Assume

ideal behaviour and use R=8.314 J/mol. K.

Your Answer:

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Answers (1)
  1. 15 June, 11:01
    0
    1.76 kg/m³

    Explanation:

    1) dа ta:

    a) Chemical formula: (CH₃) ₂CO

    b) P = 100,000 Pa

    c) T = 398 K

    d) D = ?

    e) R = 8.314 J / mol. K

    2) Principles and formulae:

    a) Ideal behaviour of a gas means that it follows the ideal gas equation:

    PV = nRT

    b) Density, D = mass / volume

    c) mass in grams = n * molar mass

    3) Solution:

    a) Transform the ideal gas equation to solve for the density:

    PV = nRT (n = mass in grass / molar mass)

    PV = (mass in grams / molar mass) RT

    (mass in grams / V) = P * molar mass / (RT)

    mass in kg * 1,000 (g / kg) / V = P * molar mass / (RT)

    (mass in kg / V) = P * molar mass / (1,000RT)

    D = P * molar mass / (1,000RT)

    b) Molar mass of (CH₃) ₂CO: 58.08 g/mol

    c) Substitute and compute:

    D = 100,000 Pa * 58.08 kg/mol / (1,000 * 8.314 J/mol. K * 398 K)

    * (note that by dividing by 1,000 the molar mass is transformed from g/mol to kg/mol)

    D = 1.76 kg/m³← answer
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