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30 August, 22:58

If 4520 kJ of heat is needed to boil a sample of water, what is the mass of the sample of water (ΔHvaporiztion = 2260kJ/kg) ?

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  1. 30 August, 23:03
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    Answer:2kg

    Explanation:heat gained=heat lost

    mass x 2260=4520

    4530:2260

    And=2kg
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