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Kristopher
Chemistry
3 October, 06:24
How many moles of o are in 15.0 mol fe (no3) 3?
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Edwin Ramirez
3 October, 06:31
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N[Fe (NO₃) ₃]=15.0 mol
n (O) = 3*3*n[Fe (NO₃) ₃]=9n[Fe (NO₃) ₃]
n (O) = 9*15.0=135.0 mol
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