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4 January, 18:19

A student is titrating 50 mL of 0.32 M NH3 with 0.5 M HCl. How much hydrochloric acid must be added to react completely with the ammonia?

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  1. 4 January, 18:47
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    The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL

    Explanation:

    Using the formula

    Ca Va = Cb Vb

    Cb = 0.32 M

    Vb = 50 mL = 50/1000 = 0.050L

    Ca = 0.5 M

    Va = ?

    Substituting for Va in the equation, we obtain:

    Va = Cb Vb / Ca

    Va = 0.32 * 0.05 / 0.5

    Va = 0.016 / 0.5

    Va = 0.032 L

    The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL
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