A solution is made by dissolving 373.5 g of Pb (NO3) 2 (molar mass: 331.2 g/mol) in 2.00 * 103 g of water. What is the molality of the solution?

Question

Leticia Clayton

Chemistry

10 October, 08:23

A solution is made by dissolving 373.5 g of Pb (NO3) 2 (molar mass: 331.2 g/mol) in 2.00 * 103 g of water. What is the molality of the solution?

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Boomer · Answer 1

Molality = moles Pb (NO3) 2 / Kg H2O

373.5 g Pb (NO3) 2 X (1 mole / 331.2 grams) = 1.13 moles Pb (NO3) 2

2.00 x 10^3 g (1 Kg / 1000g) = 2 Kg

Molality = 1.13 moles / 2 Kg = 0.565 molal.