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11 September, 11:02

How many moles of KNO3 will be required to prepare 8.0L of 1.40 M KNO3?

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  1. 11 September, 11:12
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    11.2 moles of KNO3 will be required to prepare 8.0 L of 1.40 M KNO3

    Explanation:

    To answer this question, we need an understanding of the units of the term called molarity.

    1.40M KNO3 means that there are 1.4 moles per dm^3 or per liter of the solution.

    Now, since there are 1.4 moles in 1 liter

    x moles will be present in 8.0 liters

    Thus, mathematically;

    x * 1 = 8 * 1.4

    x = 11.2 moles
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