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18 May, 12:15

Given 10.8 grams of substance Y, if the substance absorbs 231 kilojoules of energy and the specific heat of the substance is 6.55 J/g·°C, what is the change in temperature?

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  1. 18 May, 12:35
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    Q = mxcxdelta t

    or

    231 = 10.8x6.55x Delta t

    Delta t = 3.265 degrees celcius
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