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3 January, 08:27

For a solution of acetic acid (CH3COOH) to be called "vinegar," it must contain 5.00% acetic acid by mass. If a vinegar is made up only of acetic acid and water, what is the molarity of acetic acid in the vinegar? The density of vinegar is 1.006 g/mL

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  1. 3 January, 08:35
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    M = 0.838 M

    Explanation:

    1) dа ta:

    a) Acetic acid CH₃COOH

    b) molar mass of CH₃COOH: 60.052 g/mol

    c) %: = 5.00%

    d) d = 1.006 g/ml

    e) M = ?

    2) Formulae:

    a) M = n of solute / V of solution in liters

    b) n = mass in grams / molar mass

    c) % = (mass of solute / mass of solution) * 100

    d) d = mass / volume

    3) Solution:

    a) Assume a basis

    V = 1 liter of solution

    b) Calculate the mass of that basis (1 liter of solution)

    d = mass / V ⇒ mass = d * V mass = 1.006 g/ml * 1 liter * 1,000 ml/liter = 1006 g

    c) Calculate the mass of solute

    % = (mass of solute / mass of solution) * 100 ⇒

    mass of solute = % * mass of solution / 100 = 5.00% * 1,006 g / 100

    mass of solute = 50.3 g

    d) Calculate the number of moles of solute

    n = mass in grams / molar mass = 50.3 g / 60.052 g/mol = 0.838 mol

    e) Calculate molarity

    M = n / V in liter = 0.838 mol / 1 liter = 0.838 M ← answer
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