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9 December, 20:59

A 500.0 grams sample of aluminum is initially at 25.0C it absorbs 32.60 KJ of heat from its surroundings. What is it final temperature, in C?

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  1. 9 December, 21:01
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    72·45 °C

    Explanation:

    Given

    Mass of sample of aluminum is 500·0 g

    Initial temperature is 25·0 °C = 298 K

    Heat absorbed from surroundings is 32·60 kJ

    Heat capacity of aluminum is 0·9 J/g K

    Formula for amount of heat transfer is

    Q = m * s * ΔT

    where

    Q is the amount of heat transfer

    m is the mass of the substance

    s is the heat capacity of the substance

    ΔT is the change in temperature

    Let the final temperature be T K

    ∴ 32·60 * 1000 = 500 * 0·9 * (T - 298)

    T - 298 = 72·45

    ∴ T = 370·45 K = (370·45 - 298) °C = 72·45 °C

    ∴ Final temperature is 72·45 °C
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