If 4.50 mol of ethane, C2H6, undergo combustion according to the unbalanced equation C2H6 + O2 CO2 + H20, how many moles of oxygen

are required?

Question

Amelie Norton

Chemistry

19 May, 09:27

If 4.50 mol of ethane, C2H6, undergo combustion according to the unbalanced equation C2H6 + O2 CO2 + H20, how many moles of oxygen

are required?

+2

Answers (2)

Know the Answer?

Deanna Frank · Answer 1

The molecules is answer O2

Madelynn Foster · Answer 2

First balance the equation

C2H6 + 7/2O2 2CO2 + 3H2O

for one mole of C2H6 there are 7/2 mole of O2 required. so for4.50 moles you require 4.50 x 7/2 = 15.75 moles of O2.

If 4.50 mol of ethane, C2H6, undergo combustion according to the unbalanced equation C2H6 + O2 CO2 + H20, how many moles of oxygenare required?

If 4.50 mol of ethane, C2H6, undergo combustion according to the unbalanced equation C2H6 + O2 CO2 + H20, how many moles of oxygen

are required?