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19 May, 09:27

If 4.50 mol of ethane, C2H6, undergo combustion according to the unbalanced equation C2H6 + O2 CO2 + H20, how many moles of oxygen

are required?

+2
Answers (2)
  1. 19 May, 09:36
    0
    The molecules is answer O2
  2. 19 May, 09:52
    0
    First balance the equation

    C2H6 + 7/2O2 2CO2 + 3H2O

    for one mole of C2H6 there are 7/2 mole of O2 required. so for4.50 moles you require 4.50 x 7/2 = 15.75 moles of O2.
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