A gas occupies 72.1 at stp. At what temperature would the gas occupy 85.9 L at a pressure of 93.6 kPa?

328.1 K.

Explanation:

To calculate the no. of moles of a gas, we can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in.

If n is constant, and have two different values of (P, V and T):

P₁V₁T₂ = P₂V₂T₁

P₁ = 1.0 atm (standard P), V₁ = 72.1 L, T₁ = 25°C + 273 = 298 K (standard T).

P₂ = 93.6 kPa = 0.924 atm, V₂ = 85.9 L, T₂ = ? K.

T₂ = P₂V₂T₁/P₁V₁ = (0.924 atm) (85.9 L) (298 K) / (1.0 atm) (72.1 L) = 328.1 K.