Magnesium (24.48g) reacts with hydrochloric acid (xg) to produce hydrogen gas (2.04g) and magnesium chloride (96.90g). How much hydrogen chloride was used in the reaction?

Mass = 73.73 g

Explanation:

Given dа ta:

Mass of Mg used = 24.48 g

Mass of HCl used = ?

Mass of hydrogen gas produced = 2.04 g

Mass of Magnesium chloride produced = 96.90 g

Solution:

Chemical equation:

Mg + 2HCl → MgCl₂ + H₂

Number of moles of Mg:

Number of moles = mass / molar mass

Number of moles = 24.48 g / 24.305 g/mol

Number of moles = 1.01 mol

Now we will compare the moles of Mg with HCl from balance chemical equation.

Mg : HCl

1; 2

1.01 : 2/1 * 1.01 = 2.02 mol

Mass of HCl react:

Mass = number of moles * molar mass

Mass = 2.02 * 36.5 g/mol

Mass = 73.73 g