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3 December, 04:43

If you want to produce 11 moles of NH3, how much H2 do you need?

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  1. 3 December, 04:51
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    33 g of H2

    Explanation:

    N2 + 3 H2 - > 2 NH3

    3 mol H2 - > 2 mol NH3

    x - > 11 mol NH3

    x = (11 mol NH3 * 3 mol H2) / 2 mol NH3

    x = 16.5 mol H2

    1 mol H2 - > 2 g

    16.5 mol H2 - >x

    x = (16.5 mol H2 * 2 g) / 1 mol H2

    x = 33 g
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