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12 May, 18:59

The percentage yield of the following reaction is 85 %. 2 Al, + 31--> 2 AICI. How many grams of AICI, will be actually obtained from 1008 aluminium metal

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  1. 12 May, 19:05
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    Assuming the product is AlCl3

    Assuming its 1008 g of metalic Al

    It will yeld 4234 g of aluminium chloride.

    Explanation:

    Al molar mass is 26.98 g/mol, so in 1008 g of Al there is 37.36 mols of Al

    The stoichometry ratio between Al and AlCl3 is 1:1, so 37.36 mols of Al would form 37.36 mols of AlCl3 if the reaction were complete, but only 85% yelds, so 1008 g of Al makes up to 0.85x37.36 mols of AlCl3 (31.76 moles)

    AlCl3 molar mas is 133.33 g/mol, so 31.76 moles has 4234 g
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