How many grams of caf2 would be needed to produce 8.41*10-1 moles of f2?

Answer: 65.7 grams

Explanation:

1) ratio

Since 1 mole of CaF2 contains 1 mol of F2, the ratio is:

1 mol CaF2 : 1 mol F2

2) So, to produce 8.41 * 10^ - 1' mol of F2 you need the same number of moles of CaF2.

3) use the formula:

mass in grams = molar mass * number of moles

molar mass of CaF2 = 40.1 g/mol + 2 * 19.0 g/mol = 78.1 g/mol

mass in grams = 78.1 g/mol * 8.41 * 10^ - 1 mol = 65.7 grams