Calculate the density of gold (in units of g/mL) if a 5.00 cm cube has a mass of 2.41kg

Question

Keller

Chemistry

23 February, 20:48

Calculate the density of gold (in units of g/mL) if a 5.00 cm cube has a mass of 2.41kg

+2

Answers (2)

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Damon Hickman · Answer 1

Turn 2.41 kg into grams:

2.41 * 1000 = > 2,410 g

1 cm³ = 1 mL, so:

5.00 cm³ = 5.00 mL

Therefore:

D = mass / volume

D = 2,410 / 5.00

D = 482 g/mL

Rodolfo Simmons · Answer 2

The volume of a 5cm cube is 0.5dm*0.5dm*0.5dm = 0.125dm^3

1dm^3 = 1l

So 0.125dm^3 = 125mL

This gives us 2410/125 = 19.28

So the density of gold is 19.28g/mL

Final check: Gold is indeed 19.3g/mL