How much h2 gas at stp can be produced by the reaction 2 na (s) + 2 h2o (ℓ) - → h2 (g) + 2 naoh (aq) of 4.40 g of na and excess water? answer in units of l?

Question

Catwoman

Chemistry

23 November, 08:39

How much h2 gas at stp can be produced by the reaction 2 na (s) + 2 h2o (ℓ) - → h2 (g) + 2 naoh (aq) of 4.40 g of na and excess water? answer in units of l?

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Answers (1)

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Cora Camacho · Answer 1

From the reaction;

2Na (s) + 2 H2O (l) = H2 (g) + 2 NaOH (aq)

The atomic mass of sodium is 22.99 g/mol

The number of moles of sodium will be

= 4.40/22.99

= 0.1914 moles

The mole ratio of sodium and hydrogen is 2: 1

; therefore, the number of moles of hydrogen = 0.1914 / 2

= 0.0957 moles

1 mole of hydrogen at s. t. p occupies 22.4 liters, hence 0.0957 moles will occupy; 0.0957 * 22.4 = 2.144 L

Therefore, 2.144 liters of hydrogen gas will be produced