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14 March, 23:51

A normal force of 38 newtons acts on a book lying on a table. If the coefficient of static friction is 1.2, what is the minimum applied force required to slide the book?

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  1. 15 March, 00:01
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    N = normal force = 38 newtons

    Ks = coefficient of static friction = 1.2

    Ff = maximum friction force = ks*N = 1.2 * 38 newtons = 45.6 newtons

    F = minimum applied force = Ff

    F = 45.6 newtons
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