How many electrons are in 1.01 oz of a pure gold coin?

1) 1 oz = 28.3495 grams

2) atomic mass of gold = 196.967 g / mol

3) number of moles = mass in grams / molar mass

=> number of moles of gold = 28.3495 g / 196.967 g*mol = 0.144393 moles

4) atomic number of gold = 79

=> 79 protons and 79 electron per atom of gold

=> 79 * 0.144393 moles of electrons = 11.41 moles of electrons

5) Avogadro's number = 6.022 * 10^23 units / mol

11.41 moles * 6.022 * 10^23 electrons / mol = 68.72 * 10^ 23 electrons = 6.872 * 10^24 electrons

Answer: 6.872 * 10^24 moles of electrons