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18 June, 03:46

A chemist adds 150.0mL of a 0.12/molL aluminum sulfate Al2SO43 solution to a reaction flask. Calculate the mass in grams of aluminum sulfate the chemist has added to the flask. Round your answer to 2 significant digits.

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  1. 18 June, 04:16
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    The mass of aluminium sulfate is 6.20 grams

    Explanation:

    Step 1: data given

    Volume Al2 (SO4) 3 = 150.0 mL = 0.150 L

    Molarity = 0.12 mol/L

    Molar mass Al2 (SO4) 3 = 342.15 g/mol

    Step 2: Calculate moles Al2 (SO4) 3

    Moles Al2 (SO4) 3 = molarity * volume

    Moles Al2 (SO4) 3 = 0.12 M * 0.150 L

    Moles Al2 (SO4) 3 = 0.018 moles

    Step 3: Calculate mass Al2 (SO4) 3

    Mass Al2 (SO4) 3 = moles * molar mass

    Mass Al2 (SO4) 3 = 0.018 moles * 342.15 g/mol

    Mass Al2 (SO4) 3 = 6.16 grams ≈ 6.20 grams

    The mass of aluminium sulfate is 6.20 grams
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