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30 November, 16:38

Determine the volume of methane (ch 4) gas needed to react completely with 0.660 l of o 2 gas to form methanol (ch 3 oh).

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  1. 30 November, 16:46
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    Balance Chemical Equation for this reaction is,

    2 CH₄ + O₂ → 2CH₃OH

    According to this eq, 22.4 L (1 moles) of Oxygen requires 44.8 L (2 mole) CH₄ for complete reaction.

    So, the volume of CH₄ required to consume 0.66 L of O₂ is calculated as,

    22.4 L O₂ required to consume = 44.8 L CH₄

    0.660 L O₂ will require = X L of CH₄

    Solving for X,

    X = (44.8 L * 0.660 L) : 22.4 L

    X = 1.320 L of CH₄

    Result:

    1.320 L of CH₄ gas is needed to react completely with 0.660 L of O ₂ gas to form methanol (CH ₃OH).
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