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23 September, 14:23

How much heat must be absorbed by 125 of ethanol to change its temperature from 22.3 to 31.0? (Specific heat capacity of ethanol is 2.42)

a. 2.63*103kJ

b. 4.55 kJ

c. 85.2 kJ

d. 2.63 kJ

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  1. 23 September, 14:40
    0
    The heat = 2.63 kJ (option d)

    Explanation:

    Step 1: Data given

    Mass of ethanol = 125 grams

    Initial temperature of ethanol = 22.3 °C

    Final temperature of ethanol = 31.0 °C

    Specific heat of ethanol = 2.42 J/g°C

    Step 2: Calculate heat transfer

    Q = m*c*ΔT

    ⇒ with Q = the heat transfer (in joules)

    ⇒ with m = the mass of ethanol = 125 grams

    ⇒ with c = the specific heat of ethanol = 2.42 J/g°C

    ⇒ with ΔT = The change of temeprature = T2 - T1 = 31.0 - 22.3 °C = 8.7 °C

    Q = 125 grams * 2.42 J/g°C * 8.7 °C

    Q = 2632 J = 2.63 kJ

    The heat = 2.63 kJ (option d)
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