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5 May, 23:57

Find the empirical and molecular formula for a molar mass of 60.10g/mol; 39.97% carbon 13.41% hydrogen: 46.62% nitrogen

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  1. 6 May, 00:09
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    Assuming we have 100g, this means that

    39.97g Carbon * 1 mol / 12 g = 3.33 mol Carbon

    13.41g Hydrogen * 1 mol/1 g = 13.41 mol Hydrogen

    46.62g Nitrogen * 1 mol / 14 g = 3.33 mol Nitrogen

    Dividing everything by 3.33, we get

    1 mol Carbon, 4.03 mol Hydrogen, 1 mol Nitrogen.

    Empirical formula is CH4N

    The mass of the empirical formula is

    12 + 4 + 14 = 30

    Since the molar mass is double, we multiply all our subscripts

    The molecular formula is C2H8N2

    The answers to this question are an empirical formula of CH4N and a molecular formula of C2H8N2.
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