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7 March, 04:23

Fumaric acid is an organic compound composed of 41.39%, 3.47%, and the rest oxygen. If 0.288 mol of fumaric acid has a mass of 33.4 g, what are the empirical and molecular fomulas of fumaric acid

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  1. 7 March, 04:26
    0
    Molecular formula: C₄H₄O₄

    Empirical formula: CHO

    Explanation:

    Centesimal composition of fumaric acid:

    41.39% C

    3.47% H

    (100% - 41.39% - 3.47%) = 55.14% O

    In 100 g of fumaric, we got:

    41.39 g of C

    3.47 g of H

    55.14 g of O

    If we take account that we have x mol of fumaric in x mass of the same compound (g/mol), we can determine molar mass.

    33.4 g / 0.288 mol → 116 g/mol

    Now, we can prepare this rules of three:

    In 100 g of fumaric we have 41.39 g of C, 3.47 g of H, 55.14 g of O

    Then 116 g of fumaric will have:

    (116. 41.39) / 100 = 48 g C

    (116. 3.47) / 100 = 4 g H

    (116. 55.14) / 100 = 64 g O

    If we convert the mass to moles, we reach the molecular formula:

    48 g. 1mol / 12 g = 4 moles C

    4 g. 1mol / 1g = 4 moles H

    64. 1mol/16 g = 4 moles O

    Molecular formula: C₄H₄O₄

    Empirical formula: CHO
  2. 7 March, 04:29
    0
    The empirical formula is CHO

    The molecular formula is C4H4O4

    Explanation:

    Step 1: Data given

    Mass of fumaric acid = 33.4 grams

    Moles fumaric acid = 0.288 moles

    Fumaric acid contains:

    41.39 % C

    3.47 % H

    The rest of the compound is O

    Step 2: Calculate the % O

    100 - 41.39 - 3.47 = 55.14 %

    Step 3: calculate mass

    Mass C = 0.4139 * 33.4 grams = 13.82 grams

    Mass H = 0.0347 * 33.4 grams = 1.16 grams

    Mass O = 0.5514 * 33.4 grams = 18.42 grams

    Step 4: Calculate moles

    Moles = mass / molar mass

    Moles C = 13.82 grams / 12.01 g/mol = 1.15 moles

    Moles H = 1.16 grams / 1.01 g/mol = 1.15 moles

    Moles O = 18.42 grams / 16.0 g/mol = 1.15

    The empirical formula is CHO

    The molecular weight is 29.02 g/mol

    Step 5: Calculate molar mass of fumaric acid

    Molar mass = mass / moles

    Molar mass = 33.4 grams / 0.288 moles

    Molar mass = 115.97 g/mol

    Step 6: Calculate molecular formula

    115.97 / 29.02 = 4

    We have to multiply the empirical formula by 4

    4 * (CHO) = C4H4O4

    The molecular formula is C4H4O4
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