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20 January, 05:54

A sample of argon has a volume of 1.2 L at STP. If the temperature is

increased to 22°C and the pressure is lowered to 0.80 atm, what will

the new volume be, in L?

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Answers (1)
  1. 20 January, 06:06
    0
    the new volume would be 1.62 L

    Explanation:

    stp is 0 degrees C or 273.15 K and 1atm for the pressure

    22 degrees C is 295.15 K

    use the combined gas law formula and solve for v2

    v2=p1 (v1) (t2) / p2 (t1)

    v2=1atm (1.2L) (295.15) / 0.8atm (273.15K)

    v2=1.62
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