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9 October, 14:49

What is the empirical formula of a compound composed of 34.3 g of potassium (K) and

7.02 gof oxygen (O) ?

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Answers (2)
  1. 9 October, 15:00
    0
    Empirical formula is K₂O

    Explanation:

    These are the elements and their mass, from the compound

    34.3 g of K

    7.02 g of O

    We determine the moles:

    34.3 g / 39.1 g/mol = 0.877

    7.02 g / 16g/mol = 0.434

    We divide the moles, by the lowest value:

    0.877 / 0.434 = 2 mol of K

    0.434 / 0.434 = 1 mol of O

    Empirical formula is K₂O
  2. 9 October, 15:13
    0
    The empirical formula is K2O

    Explanation:

    Step 1: Data given

    Mass of potassium (K) = 34.3 grams

    Mass of oxygen (O) = 7.02 grams

    Molar mass of K = 39.1 g/mol

    Molar mass of O = 16.0 g/mol

    Step 2: Calculate moles

    Moles = mass / molar mass

    Moles K = 34.3 grams / 39.1 g/mol

    Moles K = 0.877 moles

    Moles O = 7.02 grams / 16.0 g/mol

    Moles O = 0.439 moles

    Step 3: Calculate the empirical formula

    We divide by the smallest amount of moles

    K: 0.877 moles / 0.439 moles = 2

    O: 0.439 moles / 0.439 moles = 1

    This means for each mol oxygen we have 2 moles of potassium

    The empirical formula is K2O
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